Question

2 np3 = np5 then find n​

Answer 1

Step-by-step explanation:

2 n!/(n-3)!=n!/(n-5)!

2 n!/(n-3)(n-4)(n-5)!=n!/(n-5)!

2/(n-3)(n-4)=1

2=n²-7n+12

n²-7n+10=0

n²-5n-2n+10=0

n(n-5)-2(n-5)=0

(n-2)(n-5)=0

n=5 (n=2 is not possible)