2
number.
6. The present ages of Rohit and Mayank are in the ratio 11 : 8. 8 years later the sum of
their
ages
will be 54 years. What are their present ages?
CH
11
Answers
Let's take their age as x
- Therefore, 11x + 8x = 54
- 19x = 54
- 19x = 54
- x = 54/19
- x = 2.8
11x = 11×2.8
= 31 (round of technique) = 30.8 (30 years 8 months) (not needed)
8x = 8×2.8
= 23 (round off technique) = 22.7 (22 yrs 7 mths) (not needed)
Total = 54
Question
The present ages of Rohit and Mayank are in the ratio 11:8. 8 years later the sum of their ages will be 54 years. What are their present ages?
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Answer
Let's consider present age of Rohit as 11x and present age of Mayank as 8x.
After 8 years,
Age of Rohit ⇒ 11x + 8
Age of Mayank ⇒ 8x + 8
To find their present age we need to find the value of 'x' first. We'll solve this equation to find 'x'. ⇒ (11x + 8) + (8x + 8) = 54
Let's solve your equation step-by-step.
(11x + 8) + (8x + 8) = 54
Step 1: Combine Like Terms
⇒ 11x + 8 + 8x + 8 = 54
⇒ (11x + 8x) + (8 + 8) = 54
⇒ 19x + 16 = 54
Step 2: Subtract 16 from both sides of the equation.
⇒ 19x + 16 - 16 = 54 - 16
⇒ 19x = 38
Step 3: Divide 19 from both sides of the equation.
⇒ 19x ÷ 19 = 38 ÷ 19
⇒ x = 2
∴ x = 2
∴ Present age of Rohit ⇒ 11x ⇒ 11 × 2 ⇒ 22 years
∴ Present age of Mayank ⇒ 8x ⇒ 8 × 2 ⇒ 16 years
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