Math, asked by SeemaElias, 4 months ago

2
number.
6. The present ages of Rohit and Mayank are in the ratio 11 : 8. 8 years later the sum of
their
ages
will be 54 years. What are their present ages?
CH
11​

Answers

Answered by GAMINGgurl
39

Let's take their age as x

  • Therefore, 11x + 8x = 54
  • 19x = 54
  • 19x = 54
  • x = 54/19
  • x = 2.8

11x = 11×2.8

= 31 (round of technique) = 30.8 (30 years 8 months) (not needed)

8x = 8×2.8

= 23 (round off technique) = 22.7 (22 yrs 7 mths) (not needed)

Total = 54

Answered by cαlypso
59

Question

The present ages of Rohit and Mayank are in the ratio 11:8. 8 years later the sum of their ages will be 54 years. What are their present ages?

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Answer

Let's consider present age of Rohit as 11x and present age of Mayank as 8x.

After 8 years,

Age of Rohit ⇒ 11x + 8

Age of Mayank ⇒ 8x + 8

To find their present age we need to find the value of 'x' first. We'll solve this equation to find 'x'. ⇒ (11x + 8) + (8x + 8) = 54

Let's solve your equation step-by-step.

(11x + 8) + (8x + 8) = 54

Step 1: Combine Like Terms

⇒ 11x + 8 + 8x + 8 = 54

⇒ (11x + 8x) + (8 + 8) = 54

⇒ 19x + 16 = 54

Step 2: Subtract 16 from both sides of the equation.

⇒ 19x + 16 - 16 = 54 - 16

⇒ 19x = 38

Step 3: Divide 19 from both sides of the equation.

⇒ 19x ÷ 19 = 38 ÷ 19

⇒ x = 2

∴ x = 2

∴ Present age of Rohit ⇒ 11x ⇒ 11 × 2 ⇒ 22 years

∴ Present age of Mayank ⇒ 8x ⇒ 8 × 2 ⇒ 16 years

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