2 number differ by 3 and their product is 504 find the number
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let one no. be x and the other be y
x-y = 3
x=y+3___(1)
xy=504,___(2)
put x= y+3 in (2)
(y+3)*y=504
y^2+3y-504=0
y^2+24y-21y-504=0
y(y+24)-21(y+24)=0
y=21,-24
put y=21 in (1)
x=21+3
=24
y=24====>x=27
since 24*27=648
x=24,y=21
is the correct answer
x-y = 3
x=y+3___(1)
xy=504,___(2)
put x= y+3 in (2)
(y+3)*y=504
y^2+3y-504=0
y^2+24y-21y-504=0
y(y+24)-21(y+24)=0
y=21,-24
put y=21 in (1)
x=21+3
=24
y=24====>x=27
since 24*27=648
x=24,y=21
is the correct answer
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