Question

2 numbers are in ratio of 3:7, if their sum is 70, find the numbers​

Answer 1

Answer: the required  two numbers are 21 and 49  Step-by-step explanation:  In the given problem,we have to find the two numbers  Given that, two  numbers are in the ratio of 3:7  Let, the two numbers are 3x and 7x , (where x is some proportionality constant)  Now, Given that , Sum of the two numbers is 70  Then, by given condition , we get,        3x + 7x = 70   => 10x = 70    => x = 70/10   => x = 7  Hence, one number is (3×7) = 21   and the other number is (7×7) = 49 ∴ the two numbers which are in the ratio of 3:7 and whose sum is 70 , are 21 and 49  Hence, 21 and 49 are the required numbers