Question

2 numbers are in the ratio 3:4 and their sum is equal to 56.find the numbers​

Answer 1

Answer:

Two numbers in the ratio $3:4$ are $24$ and $32$ .

Step-by-step explanation:

To find : original numbers

Given : two numbers are in the ratio $3:4$  and their sum is equal to $56$ .

Solution :

• As per given data we know that two numbers are in the ratio $3:4$  and their sum is equal to $56$ .
• Let , $3x$ and $4x$ be the two numbers .
• According to given condition we write as , $3x + 4x = 56$ .
• Using transposition method we find the value of $x$ , by transposing constants at RHS and leaving variables at LHS .

        $3x + 4x = 56 \\7x = 56 \\ x= \frac{56}{7} \\x = 8$  

• Now ,to find original numbers we substitute the value of $x$ in $3x$ and $4x$.

       $3x = 3\times 8 =24 \\4x = 4\times 8 = 32$

Answer 2

Answer:

Hence the numbers is 24 and 32.

Step-by-step explanation:

As per the details provided in the above question.

The given data is sum of two number is 56.

The ratio of numbers is 3:4.

We have to find the number.

Let us consider the ratio be 3x and 4x.

Their sum is equal to 56.

So,

$3x + 4x = 56 \\ 7x = 56$

Shifting 7 From LHS to RHS so it will transfer in denominator.

$x = \frac{56}{7} \\ x = 8$

Therefore is ratio of number is as follow.

First number is 3x

$3x = 3 \times 8 = 24$

Second number is 4x

$4x = 4 \times 8 = 32$

Hence the numbers is 24 and 32.