2 numbers are in the ratio 4:5 if the sum of these is equal to third angle. find the angles of the triangle.
Rohitpandat59:
Nice
Answers
Answered by
20
let's first angle =4x
second angle=5x
third angle=5x+4x=9x
4x+5x+9x=180
18x=180
x=10
then first angle=4x=4×10=40
second angle=5x=5×10=50
third angle=9x=9×10=90
second angle=5x
third angle=5x+4x=9x
4x+5x+9x=180
18x=180
x=10
then first angle=4x=4×10=40
second angle=5x=5×10=50
third angle=9x=9×10=90
Answered by
31
Let the common ratio between the two angles be x.
Then the angles will be 4x and 5x.
Given that the sum of these is equal to the third angle.
4x + 5x = 9x.
So, we have all three angles as 4x,5x,9x.
We know that sum of angles of a triangle = 180
4x + 5x + 9x = 180
18x = 180
x = 180/18
x = 10.
1st angle = 4x = 4 * 10 = 40
2nd angle = 5x = 5 * 10 = 50
3rd angle = 9x = 9 * 10 = 90.
Therefore the angles of the triangle are 40,50,90.
Hope this helps!
Then the angles will be 4x and 5x.
Given that the sum of these is equal to the third angle.
4x + 5x = 9x.
So, we have all three angles as 4x,5x,9x.
We know that sum of angles of a triangle = 180
4x + 5x + 9x = 180
18x = 180
x = 180/18
x = 10.
1st angle = 4x = 4 * 10 = 40
2nd angle = 5x = 5 * 10 = 50
3rd angle = 9x = 9 * 10 = 90.
Therefore the angles of the triangle are 40,50,90.
Hope this helps!
Similar questions