Question

2 numbers are such that the ratio between them is 3:5.if each is increased by 10 the ratio between the new numbers so formed is 5:7. Find the original numbers

Answer 1

Answer:

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Let the two numbers be x & y.

➡ x / y = 3 / 5

➡ x = 3y / 5 ......... (1)

➡ ( x + 10 ) / ( y + 10 ) = 5 / 7

➡ 7 ( x + 10 ) = 5 ( y + 10 )

➡ 7x + 70 = 5y + 50

➡ 7x = 5y + 50 - 70

➡ 7x = 5y - 20

• Substitute, the value of x in (1), we get

➡7 ( 3y / 5 ) = 5y - 20

➡ 21y / 5 = 5y - 20

➡ 21y = 5 ( 5y - 20)

➡ 21y = 25y - 100

➡ 25y - 21y = 100

➡ 4y = 100

➡ y = 100 / 4

➡ y = 25

• Substitute the value of y in (1)

➡ x = 3( 25 ) / 5

➡ x = 75 / 5

➡ x = 15

THEREFORE,THE VALUES OF "x = 15" & "y = 25"

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Step-by-step explanation:

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