2. O is any point in the interior of triangle PQR. OP, OQ and OR are joined.
Show that 2 (OP + OQ + OR) > PQ + QR + RP.
[Hint: From triangle OPQ, OP + OQ > PQ, from triangle OQR, OQ + OR > QR and
from triangle OPR, OP + OR > PR]
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Answer:
We know that, sum of two sides is greater than the third side.
In △OPQ
Sum of any two sides is greater than the third side.
∴OP+OQ>PQ
So, this is true.
Step-by-step explanation:
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