Physics, asked by MANIVELLOGU4189, 11 months ago

2 objects are thrown up at an angle of 45 and 60 respectively with the horizontal if both objects attain same vertical height then then ratio of magnitude of velocities with which these are projected is

Answers

Answered by Anonymous
2

θ1=30 degrees

θ2 = 60 degrees

a) Height = u² Sin² θ/2g

same height usinθ=constant

u1/u2 = Sinθ2/sinθ1

= sin60/sin30

= √3/1

Horizontal range R= u²sin2θ/g

for same hieght u² sin2θ=constant

u1/u2 =√sin2θ₂/sin2θ₁

=1/1

=1

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