Question

2 ohm and 4 ohm resistors are connected in parallel.12v potential difference is applied.find current in the circuit

Answer 1

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Answer 2

${ \bold{ \huge{ \underline{ \underline{ \red{Question:-}}}}}}$



▪ 2 Ω and 4 Ω resistors are connected in parallel. 12 V potential difference is applied. Find the current in the circuit.



${ \bold{ \huge{ \underline{ \underline{ \red{Solution:-}}}}}}$



${ \bold{ \orange{GIVEN- }}}$



✮ Resistance 1 ( R1 ) = 2 Ω


✮ Resistance 2 ( R2 ) = 4 Ω


✮ Potential difference ( V ) = 12 V


${ \bold{ \orange{TO \: FIND- }}}$



➧ Current ( I ) flowing through the circuit??


it's given in the question that the 2 resistors are connected in parallel....



${ \bold{ \underline{ \pink{for \: parallel \: combination,}}}}$


${ \bold{ \red{equivalent \: resistance \: ( \: R \: )}}}$


${ \boxed{ \bold{ \red{ \: \: \frac{1}{R } = \frac{1}{R1} + \frac{1}{R2} \: \: }}}}$

${ \bold{ \implies{ \frac{1}{R } = \frac{1}{2 \: ohm} + \frac{1}{4 \: ohm}}}}$

${ \bold{ \implies{ \frac{1}{R } = \frac{2ohm \: + \: 1 ohm}{4 {ohm}^{2} } }}}$

${ \bold{ \implies{ \frac{1}{R} = \frac{3ohm}{4 {ohm}^{2} } }}}$

${ \bold{ \implies{ \frac{1}{R } = \frac{3}{4ohm} }}}$

${ \boxed{ \bold{\implies{ \pink{R = \frac{4}{3} ohm}}}}}$

▪ applying ohm's law for calculating the current flowing through the circuit....

${ \bold{ \underline{ \underline{ \red{Ohm's \: law}}}}}$

${ \boxed{ \boxed{ \bold{ \red{ \: \: \frac{V}{I } = R \: \: }}}}}$

${ \bold{ \blue{ \frac{12 \: V}{I } = \frac{4}{3} ohm}}}$

${ \bold{ \implies{ \bold{I = \frac{12 \times 3}{4} ampere}}}}$

${ \boxed{ \boxed{ \bold{ \implies{ \pink{I = 9 \: ampere}}}}}}$

tHerefore,

the current flowing through the circuit is

9 ampere