Question

2 ohm and 4ohm connect with battery 6v calculate ammeter and voltmeter

Answer 1

Answer:

Explanation:

Energy dissipated = PtorVI×tor =I

2

Rt Joules

Consider Ohm's law V=IR.

In this case the resistors are connected in series and hence, the total resistance is 4+2=6 ohms. In a series circuit, the current remains the same throughout the circuit and so we use the I

2

Rt Joules formula.

The total current in the circuit is calculated as I=V/R=6/6=1ampere.

Therefore, the power dissipated P across the 4 ohm resistor for 5 s

= 1

2

×4×5=20Joules