Question

2 ohm and 4ohm resistors are connected in parallel . 12 V potential difference is applied . find current in the circuit​

Answer 1

Answer:

9 Amperes

Explanation:

Given :

• 2 ohms and 4 ohms resistor are connected in parallel

• 12 volts is the potential difference applied across the circuit

To find :

• Current in the circuit

Equivalent resistance :

1/equivalent resistance = 1/2+1/4

1/equivalent resistance = 2/4+1/4

1/equivalent resistance = 3/4

Equivalent resistance = 4/3

V=I×R

12=I×4/3

I=12×3/4

I=9 Amperes

The current flowing through the circuit is equal to 9 Amperes

Answer 2

Given ,

2Ω and 4Ω resistances are connected in parallel.

12 V potential difference is applied to those resistances .

We need to find the current in the circuit .

When resistances are connected in parallel . Then the resultant resistance is given by ,

$\bf R_{parallel.Eq}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+\dfrac{1}{R_3}+.....$

Given that ,

$\bf R_1=2\;\Omega\ ,\;R_2=4\;\Omega$

$\implies \bf \dfrac{1}{R_{P.Eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}\\\\\implies \bf \dfrac{1}{R_{P.Eq}}=\dfrac{1}{2}+\dfrac{1}{4}\\\\\implies \bf R_{P.Eq}=\dfrac{4*2}{4+2}\\\\\implies \bf R_{P.Eq}=\dfrac{8}{6}\\\\\implies \bf R_{P.Eq}=\frac{4}{3}\;\Omega$

So we have ,

Resistance , R = 4/3 Ω ,

Potential Difference , V = 12 V

Current , I = ? A

Now use Ohm's law to find the current .

$\implies \bf V=IR\\\implies \bf 12=I*\dfrac{4}{3}\\\\\implies \bf I=9\;Amperes$

So current in circuit is 9 Amperes