2 omega,3omega and 6omega resistors are connected in series then what will be the effective resistance of combination
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Answered by
3
Answer:
11 omega
Step-by-step explanation:
Requ ( in series ) = R1+R2+R3
R1=2omega
R2=3omega
R3=6omega
Now, Re = 2+3+6
= 11 omega
Answered by
0
Answer:
I think
Step-by-step explanation:
this answer is 11 omega
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