Question

2 one from photo plz help maths equation of straight line class 10 icse ​

Answer 1

Answer:

Solution:-

Given points are :

(x1,y1)=p(k,3)=>x1=k; y1=3

(x2,y2)=Q(8,-6)=x2=8;y2=-6

Slope=-3/4

The slope of the line segment joining the two points (x1,y1) and (x2,y2) is m=(y2-y1)/(x2-x1)

=>(-6-3)/(8-k)=-3/4

=>(-9)/(8-k)=-3/4

applying cross multiplication,then

=>(8-k)(-3)=(-9)(4)

=>-24+3k=-36

=>3k=-36+24

=>3k=-12

=>k=-12/3

=>k=-4

The value of k is -4

Answer 2

Answer:

I just want to help you if it is wrong please forgive me.