2. One of the equal sides of an isosceles triangle is 13 cm and its perimeter is 50 cm. Find the area of
the triangle.
3. The perimeter of a square is numerically equal to its area. Find its area.
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Answer:Given that one of the equal line is of 13 cm, so length of other side should also be 13 cm. ∴Length of third side is 24 cm. therefore, applying heron's formula for the area of the triangle. Therefore, area of the triangle is 60 cm^2
Step-by-step explanation:
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Step-by-step explanation:
2. let the sides of triangle be AB, BC, CA.
As isosceles triangle is the triangle that have 2 equal sides and one equal side is AB= BC = 13cm
we are given that
perimeter = 50cm
AB + BC + CA = 50cm
13 +13 + CA = 50
26 + CA = 50
CA = 50 - 26
CA = 24cm.
3. As perimeter of square = 4 × side
area = side × side
= (side) square
so it is basically numerically equal to the area
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