Question

2 One student uses a lens of focal length 50 cm and another of-50 cm What is the nature of
lens and power of lens used by each of them?​

Answer 1

Answer:

Since the focal length is negative, therefore the lens is concave lens because the focal length of concave lens is negative.

P (in diopter) =  1/f(in meters)

F = -50cm = -0.5m (1m = 100cm)

⇒ P =  -1/0.5=-2

Hence power of lens is -2 Diopter.

vice versa for positive lens

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Answer 2

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