Question

2(p-q)^2-3(p-q) factorise

Answer 1

Answer:

Step-by-step explanation:

2(p-q)^2-3(p-q). Taking (p-q) common from both the terms, we have

= (p-q)×[2×(p-q) - 3×1]

= (p-q)×[2p-2q-3]

= (p-q)(2p-2q-3)