Question

2(p2 - p+4)+6 and find its value at p=0

Answer 1

p=0(given)

2(0-0+4)+6

0-0+8+6=14

14 is the answer

Answer 2

Given :
Value of p = 0

Equation : $\sf{2 ( p^2 - p + 4 ) + 6}$

Putting the value of p in the equation.

$\sf{2(0 {}^{2} - 0 + 4) + 6}$

$\sf{ = 2 \times (4) + 6}$

$\sf{ = 8 + 6}$

$\sf{ = 14}$

Thus,

Value = 14

Thanks!