2 particles are projected vertically upwards from points (0,0) & (1,0) with uniform velocity 10 m/s & V m/s respectively, as shown in fig. It is found that they collide after time 't'. Find 'v' & 't'
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Considering motion in horizontal direction,time taken to collide,
t=2103−2v1
t=106−2v22...(1)
In vertical direction, 10×21t−21gt2=2v×t−21gt2
5=2v
v=52
t=56−10222=1.49 seconds
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see the attachment also
=1.49 seconds
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