Question

2 particles of mass 1 kg and 5 kg have same momentum calculate ratio of their kinetic energy

Answer 1

We all know that kinetic energy of a body is equal to 1/2 mv², where m is the mass of that body, and v is the velocity of the body.

Now, we can easily express this formula of kinetic energy in terms of linear momentum. We already know, that p = mv (where, p is the linear momentum of the body).

K. E. = Kinetic Energy

p = Linear Momentum

m = Mass Of The Body

v = Velocity Of The Body



Now, K. E. = $\frac{1}{2} \times m \times {v}^{2}$

Or, K. E. = $\frac{m {v}^{2} }{2}$

Or, K. E. = $\frac{ {m}^{2} {v}^{2} }{2m}$

Or, K. E. = $\frac{m \times v \times m \times v}{2m}$

Or, K. E. = $\frac{p \times p}{2m}$

Or, K. E. = $\frac{ {p}^{2} }{2m}$


Now, we will be able to find out the solution of the question mentioned easily. Also, the solution is mentioned, at the top of this answer, where a picture is attached.

Answer 2

Answer:

please refer the attachment

Explanation:

please click red hearts