Question

2 particles of masses m and 2m have equal kinetic energy.their debroglie wavelength are in the ratio

Answer 1

Answer:

We know

$\lambda = \frac{h}{p} = \frac{h}{ \sqrt{2mk} } \\ \\ so \: when \: kinetic \: energy \: is \: equal \: \\ then \\ \\ \lambda \: \: \: \: \: \alpha \: \: \: \: \: \frac{1}{ \sqrt{m} } \\ \\ so \: ratio \: will \: be \\ \\ \frac{ \lambda1}{ \lambda2} = \frac{ \frac{1}{ \sqrt{1} } }{ \frac{1}{ \sqrt{2} } } = \sqrt{2}$