Question

2 Passage-1: The legs of a right angled triangle are in the ratio 3:4 and its area is 1o14
the perimeter of the triangle is?​

Answer 1

Answer:

So, Thus the legs of the right triangle is 39 cm and 52 cm.

Answer 2

so, 3x=3× (13)= 39

4x=4×(13)=52

so now, the perimeter of the triangle =

$a + b + \sqrt{a {}^{2} + b { }^{2} }$

=

$39 + 52 + \sqrt{39 {}^{2} } + 52 {}^{2}$

=156

so the required answer is 156