Question

2 pe power 7 ° 3 pe powr 9
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6 pe power 6 ° 3²



⭐ law of indices ⭐

Answer 1

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⭐LAW OF INDICES
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Answer 2

Here is your solution

$= \frac{2 {}^{7} \times 3 {}^{7} }{6 {}^{6} \times 3 {}^{2} } \\ \\ = \frac{2 {}^{7} \times 3 {}^{7} }{(2 \times 3) {}^{6} \times 3 {}^{2} } \\ \\ = \frac{2 {}^{7} \times 3 {}^{7} }{2 {}^{6} \times 3 {}^{6} \times 3 {}^{2} } \\ \\ = 2 {}^{7} \times 3 {}^{7} \times 2 {}^{ - 6} \times 3 {}^{ - 6} \times 3 {}^{ - 2} \\ = 2 {}^{7 - 6} \times 3 {}^{9 - 8} \\ = 2 {}^{1} \times 3 {}^{1} \\ = 6$

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