Math, asked by sudeepbiswa958, 9 months ago

2 people standing on same sise of a tower in a straight line with it measures the angle of elevation of tower 25degree and 50 degree ..if height of tower is 70m..find distance between 2 people??

Answers

Answered by monish3770
1

Answer:

ANSWER

Let AB be the tower of height 70m.

Now,

For first person:-

θ=50°

AB=70m

As we know that,

tanθ=

Base

Perpendicular

Therefore,

In △ABD,

tan50°=

BD

AB

⇒BD=

tan50°

70

.....(1)

Similarly, for second person:-

θ=25°

AB=70m

In △ABC,

tan25°=

BC

AB

⇒BC=

tan25°

70

.....(2)

Therefore,

Distance between the two people

=BC−BD=

tan25°

70

tan50°

70

=70(

tan25°

1

tan50°

1

)

=70(

tan25°

1

2tan25°

1−tan

2

25°

)

=

tan25°

70

(1+tan

2

25°)

=(

tan25°

70

)sec

2

25°

=

sin25°cos25°

70

=

sin50°

140

Hence the distance between the two peope is

sin50°

140

.

Answered by dasgitanjali007
1

Answer:

1- PEOPLE ARE STANDING ON SAME SIZE OF A TOWER IN A STRAIGHT LINE WITH IT MEASURES THE ANGLE OF ELEVATION OF TOWER :- 25° AND 50°

HEIGHT OF THE TOWER :- 70M

TO FIND THE DISTANCE BETWEEN 2 PEOPLE :- ??

ATQ

ANSWER IS READY

BUT YOU NEED TO SIMPLIFY.

OK

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