2 people standing on same sise of a tower in a straight line with it measures the angle of elevation of tower 25degree and 50 degree ..if height of tower is 70m..find distance between 2 people??
Answers
Answer:
ANSWER
Let AB be the tower of height 70m.
Now,
For first person:-
θ=50°
AB=70m
As we know that,
tanθ=
Base
Perpendicular
Therefore,
In △ABD,
tan50°=
BD
AB
⇒BD=
tan50°
70
.....(1)
Similarly, for second person:-
θ=25°
AB=70m
In △ABC,
tan25°=
BC
AB
⇒BC=
tan25°
70
.....(2)
Therefore,
Distance between the two people
=BC−BD=
tan25°
70
−
tan50°
70
=70(
tan25°
1
−
tan50°
1
)
=70(
tan25°
1
−
2tan25°
1−tan
2
25°
)
=
tan25°
70
(1+tan
2
25°)
=(
tan25°
70
)sec
2
25°
=
sin25°cos25°
70
=
sin50°
140
Hence the distance between the two peope is
sin50°
140
.
Answer:
1- PEOPLE ARE STANDING ON SAME SIZE OF A TOWER IN A STRAIGHT LINE WITH IT MEASURES THE ANGLE OF ELEVATION OF TOWER :- 25° AND 50°
HEIGHT OF THE TOWER :- 70M
TO FIND THE DISTANCE BETWEEN 2 PEOPLE :- ??
ATQ
ANSWER IS READY
BUT YOU NEED TO SIMPLIFY.
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