Question

2 persons A and B could finish the work in 6 days .They worked together 4 days then A was called of and remaining work was completed by B in y days In how many days could each of them do it

Answer 1

Let A takes x number of days and B takes y number of days to complete work individually.

Therefore, 1/x +1/y = 1/p

In q days they can complete q/p work

Remaining work is 1 - q/p = (p-q)/p

This work is done by B in r days =>((p-q)/p)/(1/y) = r

Therefore, 1/y = (p-q)/p*r

Hence 1/x = 1/p - (p-q)/p*r = (r-p+q)/p*r

Therefore, A takes p*r/(r-p+q) days and B takes p*r/(p-q) days.