2 pillars of equal height stand on either side of a road, which is 200 m wide. the angle of elevation of the tops of the pillar are 60 degree and 30 degree at a point on the road between the pillars and height of each pillar
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Let the height of the equal pillars be AB = CD = h Given width of the road as BD = 100 m Let BE = x Hence DE = 100 – x In right ΔABE, θ = 60°

In right ΔCDE, θ = 30°

Thus the height of the equal pillars is 25√3 m.
Let the height of the equal pillars be AB = CD = h Given width of the road as BD = 100 m Let BE = x Hence DE = 100 – x In right ΔABE, θ = 60°

In right ΔCDE, θ = 30°

Thus the height of the equal pillars is 25√3 m.
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