Question

2 pistons of hydraulic Jack having an area of cross section 2800 cm and 50cm square.What is the force exerted on the larger piston when 25 newton force is applied on the smaller piston

Answer 1

Answer:

350 N

Explanation:

According to Pascal's law, F1/F2 = A1/A2.

F1 = 25 N

A1 = 50 cm = 0.5m

A2 = 2800 cm = 28m

F2 = (28 × 25)/0.5 = 350 N