Question

2 plate each with the charge of 1 microcoulomb are located 3 cm apart in air then find the electric force between them​

Answer 1

HOPE IT HELPS :

Electrostatic force of attraction :

Q1 = Q2 = Q = 1 micro-coulomb or $10^{-6}$ coulomb

Distance between ( r )  = 3 cm or ( 3 x $10^{-2}$ ) m

Using coulomb law of Electrostatic force :

F = [ ( 9 x $10^{9}$ ) x ( Q1 . Q1) ] / $r^{2}$

Solving the above expression we get :

F = 10 N

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Answer 2

Answer:

hope it helps u

Explanation:

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