Question

2 poin
Q9: If 15th and 23rd terms of an AP are 91 and 139 respectively then the
19th term of that AP is *​

Answer 1

Step-by-step explanation:

given :15th and 23rd term of an AP are 91 and 139.

a15=a+14d. and a23=a+22d

91=a+14d.— (1) 139=a+22d—(2)

Subtracting 1 and 2

a+14d=91

-a-22d=-139

ans

-8d=-48

d=6

now put d=6 in 1 equation

a+14d=91

a+14(6)=91

a+84=91

a=7

now find 19th term of an ap

a19=a+18d

a19=7+18(6)

a19=7+108

a19=115 and.

hope this ans help you to solve this question