Physics, asked by vi6sw9arajiasky, 1 year ago

2 point charges of +16 microcoulomb and -9 microcoulomb are placed 8 cm apart in air. Determine the position of the point where resultant electric field is 0 ( zero).

Answers

Answered by khansaab1
45
when electric field is zero
q/4π€r²= q/4π€r'²
9×10power9 ×16×10power-6/r² =9×10power9×9×10 power-6/(0.08-r)²
144/r²=81/(0.08-r)²
12/r=9/(0.08-r)
9r=0.96-12r
21r=0.98
r=4.6cm from 16 micro coloumb
Answered by vandanak1412
19

Answer:

Explanation:

               

             

        given:  Distance between two charges is 8cm    

                   let a point q is placed from distance  x from  -9mc

              now, distance from  +16mc to point charge q = [8+x] cm    

                   force of electric field  of both the charges must be equal

                  so that the resultant electric field is 0

                            F=k q / r^2

                            F1= k×16/ [8+x]^2     F2= k×9/ x^2

                                F1=F2

                       k×16/ [8+x]^2= k×9/x^2

                           square root on both sides

                                   4/[8+x] = 3/ x    

                                  3 [8+x] = 4x

                                24+3x = 4x  ⇒ 4x-3x = 24

                                       x = 24

                  therefore, the position of point q where resultant                   electric field is zero is  24

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