Question

2 point
Q15. ABCD is a rhombus whose diagonals intersect at E. If ZEAB = 40
degrees , find LABE.​

Answer 1

Answer:

Given ABCD is a rhombus and diagonals intersect at E

Since in a rhombus diagonals bisect each other

∣

EA

∣=∣

EC

∣ and ∣

EB

∣=∣

ED

∣

but since they are opposite to each other they are of opposite signs

⇒

EA

=−

EC

and

EB

=−

ED

⇒

EA

+

EC

=

O

...(i) and

EB

+

ED

=

O

Add (1) and (2)

⇒

EA

+

EB

+

EC

+

ED

=

O .....