Question

2 points
12. Find the equation of the hyperbola with vertices (0, +6) and eccentricity is
A) 5y? – 4x==180 B) 4y? – Sx?=180 c) Sy? – 6x2-180 D) none of these
D
A​

Answer 1

Answer:

Answer

Vertices(±5,0)Foci(±7,0)

a=±5 and ae=±7

And e=

5

7

We know e=

1+

a

2

b

2

On squaring both sides we get:

e

2

=1+

a

2

b

2

Or

25

49

=1+

25

b

2

Or

25

b

2

=

25

24

b

2

=24

The equation of hyperbola is

25

x

2

−

24

y

2

=1

24x

2

−25y

2

=600

Hence, Option [A] and [C] are correct.