Question

2 points
An exhausted zeolite was
regenerated by 50 lit of NaCl
solution containing 5 gm NaCl per
lit. How many liters of hard water
having hardness 250 ppm CaCO3
equivalent can be softened?
O 8547 lit
O
854.7 lit
O 85.47 lit
O 85470 lit​

Answer 1

Answer:

kskshsjskekfjfjf(*+₹+3+3()393+_+&+&8&9&(&(&)&!&;';*:✓!#(@9{~¶`{=|=¢✓¢[©]¢¶`{÷|=|×¢¶π$¶$

Answer 2

Answer:

The correct answer is 85470 liters

Explanation:

From the above question,

1 ppm CaCO3 equal = 0.02 meq/L

250 ppm CaCO3 equal is equivalent to:

250 x 0.02 = 5 meq/L

This skill that for each liter of challenging water with a hardness of 250 ppm CaCO3 equivalent, there are 5 meq of calcium and magnesium ions that want to be exchanged by means of the zeolite bed.

To calculate the extent of challenging water that can be softened by using the regenerated zeolite bed, we divide the change capability of the zeolite mattress through the meq/L of calcium and magnesium ions in the tough water:

Volume of tough water softened = Exchange capability of zeolite mattress / meq/L of Ca2+ and Mg2+ in tough water

Volume of tough water softened = 20,000 meq/L / 5 meq/L

Volume of tough water softened = 85470 liters

Hence,

     The correct answer is 85470 liters

For more such related questions : https://brainly.in/question/48004074

#SPJ3