Question

2 points
Calculate the numerical aperture
of fiber with core index n1= 1.65
and cladding index n2= 1.53
O 0.43
O 0.55
0 0.61
O 0.78​

Answer 1

Explanation:

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Answer 2

Answer:

Numerical Aperture of Fibre is $= 0.617737808459$

The option C is correct

Explanation:

Given:

$\mathrm{n} 1=1.65 \quad$ #Core index

$\mathrm{n} 2=1.53 \quad$#Cladding index

Find: The numerical aperture of fiber

Step1: The numerical aperture (NA) of the fiber is the sine of that maximum angle of an incident ray with respect to the fiber axis. It can be calculated from the refractive index difference between core and cladding, more precisely with the following relation:

$N A=\sqrt{n_{\text {core }}^{2}-n_{\text {cladding }}^{2}}$

NA =math. sqrt (n1**2-n2**2) #Formula

print"Numerical Aperture of Fibre is $={ }^{\prime \prime}$, NA

Numerical Aperture of Fibre is $=0.617737808459$