Question

2 points For given hypothetical elementary parallel reaction where K,:K=1:2. Initially only 2 moles of A are present then total number of moles A,B and C at the end of 75% reaction are-​

Answer 1

Answer:

Correct option is

D

3.5

Initial number of moles of A = 2.

The reaction is 75% complete.

The number of moles of A that has reacted =2×  

100

75

​

=1.5 moles.

The number of moles of A that has remained unreacted =2−1.5=0.5 moles.

Now,  

we have,  

k  

2

​

 

k  

1

​

 

​

=  

2

1

​

 

Hence, the number of moles of A that has reacted to form C is twice the number of moles of A that has reacted to form B.

Hence, out of 1.5 moles of A, 0.5 moles of A has reacted to give 2×0.5=1 mole of B.

Also, 1 mole of A has reacted to give 2×1=2 moles of C.

Total number of moles present after the 75% completion of the reaction is 0.5  moles A + 1 mole  B + 2 moles C = 3.5 moles.

Explanation:

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