2 points
If 3 positive integers a.b.c
are in AP such that a+b+c=33
and axbxc = 1155, then the
terms a,b,care
O 7,10,13
O 7,11,15
07.12.17
O 7,15,23
Answers
Answered by
0
Answer:
Correct option is
B
2
2/3
We know, from AM≥GM, for positive quantities, that
3
(a+b+c)
≥
3
abc
3
(a+c)+b
≥
3
abc
But 2b=(a+c).
This implies
3
3b
≥(4)
1/3
b≥(2)
2/3
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