Question

2 points

If a particle  completes motion in vertical circle, then minimum tension in the string at the lowest point is ........

five times of the weight of the particle

three times of the weight of the particle

four times of the weight of the particle

six  times of the weight of the particle

plz don't speed​

Answer 1

Answer:

sry dear you search from Google too .

Answer 2

Answer:

Hi Friend,

First of all, when such questions appear, tink about ENERGY CONSERVATIONS.

Plus, to complete a complete rotation, the string must remain tight throughout the motion

When the string is vertically upwards ,

mv^2 /r = mg ---------- v = $\\ \sqrt{rg\\}$

Initially, kinetic energy would be K ( equal to 1/2 mv^2)

1/2 mv^2 = 2mgR + 1/2 m RG

mv^2 = 5mgR

v= root of 5gr

Tension would be equal to mg + mv^2 /r

---- mg + 5mg = 6mg

Therefore 6 times the weight of the particle.