Question

2 points
In a right triangle ABC, right
angled at B, AC = 5cm, AB = 4cm,
find BC.​

Answer 1

$\huge{\mathfrak{\underline{❥answer}}}</p><p>$

☯ According to Pythagorean theorem,

${(AB)}^{2} + {(BC)}^{2} = {(AC)}^{2}$

${4}^{2} + {BC}^{2} = {5}^{2}$

$16 + {BC}^{2} = 25$

${BC}^{2} = 25 - 16$

${BC}^{2} = 9$

$BC = \sqrt{9}$

$BC = 3$

☛ 3 cm is the answer

Answer 2

$\huge\mathtt{{\underline{\underline{\orange{AnSwEr!}}}}}$

$\small{ }$

$\large\rm{{\underline{\underline{\color{indigo}{According~to~Pythagoras~theorem:}}}}}$

$\large\rm{~~~~~~~~~~(AC)^2=(AB)^2+(BC)^2}$

$\large\implies\rm{(BC)^2=(AC)^2-(AB)^2}$

$\large\implies\rm{(BC)^2=5^2-4^2}$

$\large\implies\rm{(BC)^2=25-16}$

$\large\implies\rm{(BC)^2=9}$

$\large\implies\rm{BC={\sqrt{9}}}$

$\large\therefore\rm{BC={\underline{\underline{3cm}}}}$

$\small{ }$

$\huge\bold\orange{Brainliest~Please!}$