Question

2 points
Q14. Which of the following
are correct zeros of the
polynomial p(y)=(y-1)(y-2)?
निम्न में से कौन से p(y)=(y-1)(y-2) के
शून्यक है?
O y=0,0
O y=1,2
O y=-1,-2
Oy=2, -2​

Answer 1

Step-by-step explanation:

(i) p(y)=y

2

−y+1

p(0)=(0)

2

−(0)+1=0+0+1=1

p(1)=(1)

2

−(1)+1=1−1+1=1

p(2)=(2)

2

−(2)+1=4−2+1=3

(ii) p(t)=2+t+2t

2

−t

3

p(0)=2+(0)+2(0)

2

−t

3

=2+0+0−0=2

p(1)=2+(1)+2(2)

2

−(1)

3

=2+1+2−1=4

p(2)=2+(2)+2(2)

2

−(2)

3

=2+2+8−8=4

(iii) p(x)=x

3

p(0)=(0)

3

=0

p(1)=(1)

3

=1

p(2)=(2)

3

=8

(iv) p(x)=(x−1)(x+1)

p(0)=(0−1)(0+1)=(−1)(1)=−1

p(1)=(1−1)(1+1)=(0)(2)=0

p(2)=(2−1)(2+1)=(1)(3)=3