2 points
The sum of upper limit of modal class and lower limit of median
class in the given data is :
Class 0 – 10 | 10 - 20 20 - 30
10 - 20 20 - 30 | 30 - 40 40 - 50
Frequency 6
10
12
8
7
Answers
Answer:
a class of 60 students, the marks obtained in a monthly test were as under, (5)
Marks 10 – 20 20 – 30 30 – a class of 60 students, the marks obtained in a monthly test were as under, (5)
Marks 10 – 20 20 – 30 30 – 40 40 – 50 50 – 60
Students 10 25 12 8 5
Draw a Frequency polygon to represent above data. 40 – 50 50 – 60
Students 10 25 12 8 5
Draw a Frequency polygon to represent above data.a class of 60 students, the marks obtained in a monthly test were as under, (5)
Marks 10 – 20 20 – 30 30 – 40 40 – 50 50 – 60
Students 10 25 12 8 5
Draw a Frequency polygon to represent above data.a class of 60 students, the marks obtained in a monthly test were as under, (5)
Marks 10 – 20 20 – 30 30 – 40 40 – 50 50 – 60
Students 10 25 12 8 5
Draw a Frequency polygon to represent above data.
Step-by-step explanation:
a class of 60 students, the marks obtained in a monthly test were as under, (5)
Marks 10 – 20 20 – 30 30 – 40 40 – 50 50 – 60
Students 10 25 12 8 5
Draw a Frequency polygon to represent above data.a class of 60 students, the marks obtained in a monthly test were as under, (5)
Marks 10 – 20 20 – 30 30 – 40 40 – 50 50 – 60
Students 10 25 12 8 5
Draw a Frequency polygon to represent above data.a class of 60 students, the marks obtained in a monthly test were as under, (5)
Marks 10 – 20 20 – 30 30 – 40 40 – 50 50 – 60
Students 10 25 12 8 5
Draw a Frequency polygon to represent above data.a class of 60 students, the marks obtained in a monthly test were as under, (5)
Marks 10 – 20 20 – 30 30 – 40 40 – 50 50 – 60
Students 10 25 12 8 5
Draw a Frequency polygon to represent above data.