Question

2 points
Zeroes of P(x) = x2 - 2x - 3 are
3 and 1
-3 and -1
1 and -3
3 and -1​

Answer 1

Answer:

3 and -1

Step-by-step explanation:

x^2 - 2x - 3

= x^2 - 3x + x -3

= x( x - 3) +1 ( x -3 )

= ( x - 3)( x + 1 )

Therefore,

x = 3 and x = -1

So the zeros are 3 and -1