2 poles of height 6 centimetre and 11 are placed at a distance between them is 12 centimetres , them the distance between their top is
Answers
Answer:
Let, BD be the distance between the two poles
Assume, BD = x
As △BED is a right-angled triangle right angled at E, therefore 'x' is the hypotenuse.
Now apply the Pythagoras theorem on △BED ,
Hypotenuse2 = Perpendicular2 + Base2
=> BD2 = ED2 + BE2
=> x2 = 122 + 52
=> x2 = 144 + 25
=> x2 = 169
=> x = 13 m
Therefore, the distance between the top of the two poles is 13 m
Answer:
13 cmheight of 1 rod =6 com
height of second rod 2 = 11 cm
distance =12 cm
draw a straight line from the the top of rod 1
the distancec=12 cm as the length of the initial distance
and find how much rod 2 is taller than rod 1 = 5cm
no we have have got base and height and the angle is right angle triangle
we will put pythgorna theory
base ²+ height ²= hypotenmus ²
5²+12²= hypo ²
25 + 144= hypo ²
169 =hypo ²
hypo = underfoot of 169
hypo =13 cm
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