2 poles of height 6m and 11m stand on a plane ground. If the distance between their feet is 12m, find the distance between their top.
Plz solve and write the final answer
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Answered by
2
given distance between tops of poles= 12m the poles of heights 6m & 11m ,difference lengths of poles= 5m
draw the line to longer pole form the top of shorter pole perdicularly and also join the tops of poles,clearly a right angled triangle is formed.
let the distance between their tops be x m
by pythagorus theorem x²=12²+5²=144+25=169
the value of x is 13,therefore distance between their tops is 13m.
i hope its helps u
draw the line to longer pole form the top of shorter pole perdicularly and also join the tops of poles,clearly a right angled triangle is formed.
let the distance between their tops be x m
by pythagorus theorem x²=12²+5²=144+25=169
the value of x is 13,therefore distance between their tops is 13m.
i hope its helps u
Answered by
1
Area of trapezium = (sum of parallel sides)×height/2
=(6+11)×12/2
=17×12/2
=204/2
=102
=(6+11)×12/2
=17×12/2
=204/2
=102
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