Question

2 por
13. A cyclist moves at 12 m/s for 1 min and at 16 m/s for 2 min. Find the
average velocity if the second part of the motion is in the same direction
as the first?
O 15 m/s​

Answer 1

Explanation:

Answer must be 14.66 m/sec

hope it helps

Answer 2

The average velocity the average velocity is 14.66 m/sec.  

Explanation:

Given:

Cyclist moves at 12 m/s for 1 min.

Cyclist moves  at 16 m/s for 2 min.

The second part of the motion is in the same direction as the first

To Find:

The average velocity of the Cyclist.

Solution:

As given,cyclist moves at 12 m/s for 1 min.

Cyclist velocity =12 m/s , 1st part, time =1 min =60 Sec.

$Velocity=\frac{Displacement}{Time}$

$1st\ part,\ displacement = 12\times60=720 m.$

As given,cyclist moves at 16m/s for 2 min.

Cyclist velocity =16 m/s ,  2nd. part time=2 min = 2 x 60 Sec.= 120 Sec.

Total Time= 1st part time +2nd part time

                 =60+120=180 sec.

$Velocity=\frac{Displacement}{Time}$

$2nd\ part,\ displacement = 16\times 120= 1920m.$

Total Time= 1st part time +2nd part time

                 =60+120=180 sec.

Total displacement = 1st part displacement+2nd part  displacement

                                 =720+1920=2640 m

$Average \ Velocity=\frac{ Total \ dispacement}{ Total\ times}$

                            $=\frac{1920}{180} =14.66\ m/sec$

Thus,the average velocity is 14.66 m/sec.

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