2 power 2+log 3 base 2
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Answered by
329
Hi ,
We know that
__________________________
i ) a^m+n = a^m × a^n ------( 1 )
ii) a^log (base a) ( x ) = x ----- ( 2 )
_________________________
According to the problem given,
2^2 + log ( base 2 ) ( 3 )
= 2^2 × 2^ log ( base 2 )(3 ) [ from (1)]
= 4 × 3 [ from ( 2 )]
= 12
I hope this helps you.
*****
We know that
__________________________
i ) a^m+n = a^m × a^n ------( 1 )
ii) a^log (base a) ( x ) = x ----- ( 2 )
_________________________
According to the problem given,
2^2 + log ( base 2 ) ( 3 )
= 2^2 × 2^ log ( base 2 )(3 ) [ from (1)]
= 4 × 3 [ from ( 2 )]
= 12
I hope this helps you.
*****
Answered by
245
12 is the answer.
Here this is In the form of a^m+n, just we have to change into a^m.a^n......
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