Question

2 power 2–log5 base 2​

Answer 1

Answer:

${2}^{2 - log_{2}(5) } = \frac{ {2}^{2} }{ {2}^{ log_{2}(5) } } \\ = \frac{ {2}^{2} }{5} \\ = \frac{4}{5}$

Answer 2

Given data: $2^{2-log_{2}^5 }$

To find: The value of given data

Solution:

• Power of the number is define as the multiple of same number to the count of power.
• Log is defined as the power with base value and it is raised to give number.
• Formula for logarithmic is $log_{b} (b^{x} )=x$ where b is the logarithmic base.
• Considering the given data $2^{2-log_{2}^5 }$ is written as $2^{log_{2}^4-log_{2}^5 }$ ( $log_{2}^4=2$).
• When base are same we need to add the powers $2^{log_{2}^\frac{4}{5} }$ ($2^{log_{2}=1 }$ binary log value).
• Hence the value of given data is $\frac{4}{5}$.