2 power n subtract 2 power n-1=4
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Step-by-step explanation:
(2^n-2)^n-1 =4
(2)^(n-2) (n-1) =2²
when bases are equal then powers are also equal
so,(n-2) (n-1) =2
n²-n -2n+2 =2
n²-3n +2 =2
n²-3n=2-2
n²-3n=0
n(n-3) = 0
n-3=0*n
n-3=0
so,n=3
Hope this will help you!
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