2 power x + 1 is equals to 3 power x- 1 find x value
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2^(x +1) = 3^(x - 1)
take the log of both sides:
log[ 2^(x + 1) ] = log [ 3^(x - 1) ]
log(a^b) = b * log(a)
(x + 1) * log(2) = (x - 1) * log(3)
x * log(2) + 1 * log(2) = x * log(3) - 1 * log(3)
x * log(2) - x * log(3) = -1 * log(3) - 1 * log(2)
x * [ log(2) - log(3) ] = -log(3) - log(2)
divide both sides by [ log(2) - log(3) ]:
x = [ -log(3) - log(2) ] / [ log(2) - log(3) ] = 4.52
Hope this helps u...
take the log of both sides:
log[ 2^(x + 1) ] = log [ 3^(x - 1) ]
log(a^b) = b * log(a)
(x + 1) * log(2) = (x - 1) * log(3)
x * log(2) + 1 * log(2) = x * log(3) - 1 * log(3)
x * log(2) - x * log(3) = -1 * log(3) - 1 * log(2)
x * [ log(2) - log(3) ] = -log(3) - log(2)
divide both sides by [ log(2) - log(3) ]:
x = [ -log(3) - log(2) ] / [ log(2) - log(3) ] = 4.52
Hope this helps u...
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