Question

2. PQR is a triangle, right angled at Q. IF PR-13cm, PQ-12cm then find QR.

Answer 1

Answer:

QR=5cm

Step-by-step explanation:

using Pythagoras theorem

AC²=AB²+BC²

Therefore

PR²=PQ²+QR²

13²=12²+QR²

169=144+QR²

169-144=QR²

25=QR²

5=QR

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Answer 2

Answer:

${(pr)}^{2} = {(pq)}^{2} + {(qr)}^{2} \\ therefore \: \: \: {13}^{2} = {12}^{2} + {x}^{2} \\ 169 = 144 + {x}^{2} \\ {x}^{2} = 169 - 144 \\ {x}^{2} = 25 \\ x = 5$

therefore QR = 5cm

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