Question

2
Proot & L BAC + LABC + LACB=
:: Sume of the angles of a triangle
1 LBACT 1 tI LACB= 1x
2
2
2
2
i 1 CBAC + LPBC + LPCB =
2
i. ZYBC + L P (B = 90° - 1 LBAC
2
In A BPC
LBPL + LPBL + L PCB = 180°
ZBPC +
- 180 °
LBPC = 180°/90°- ILBAC
2
(​

Answer 1

Answer:

plz rewrite the question....